2/3log ba = xx^2log3243 = xsubtracttheexponentsNo, in Step 2, Haileyshould have alsomultipliedthe exponent of thecoefficient by 2 to get32.k(x) > f(x)when x >0f(x) =268(0.86)^x$0.54perweekf (x) =975 (1 .03)^xf( x )=2^x/4x =log2(3)Allison'sby$3.953.29In10/4Theinvestment isdecreasing atthe rate of 23%every year.The functionrepresentsexponentialgrowth.8,579yearsf (x) =4(1.05)^nf(x) =200(0.92)^x1.4yearsf(x) is less thang(x) for thesame values ofx asx approachesnegative infinity.x =216f(x) =(0.005)(1.005)x2/3log ba = xx^2log3243 = xsubtracttheexponentsNo, in Step 2, Haileyshould have alsomultipliedthe exponent of thecoefficient by 2 to get32.k(x) > f(x)when x >0f(x) =268(0.86)^x$0.54perweekf (x) =975 (1 .03)^xf( x )=2^x/4x =log2(3)Allison'sby$3.953.29In10/4Theinvestment isdecreasing atthe rate of 23%every year.The functionrepresentsexponentialgrowth.8,579yearsf (x) =4(1.05)^nf(x) =200(0.92)^x1.4yearsf(x) is less thang(x) for thesame values ofx asx approachesnegative infinity.x =216f(x) =(0.005)(1.005)x

Unit 5 - Call List

(Print) Use this randomly generated list as your call list when playing the game. There is no need to say the BINGO column name. Place some kind of mark (like an X, a checkmark, a dot, tally mark, etc) on each cell as you announce it, to keep track. You can also cut out each item, place them in a bag and pull words from the bag.


1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
  1. 2/3
  2. log b a = x
  3. x^2
  4. log3 243 = x
  5. subtract the exponents
  6. No, in Step 2, Hailey should have also multiplied the exponent of the coefficient by 2 to get 3 2 .
  7. k(x) > f(x) when x > 0
  8. f(x) = 268(0.86)^x
  9. $0.54 per week
  10. f (x) = 975 (1 . 03)^x
  11. f( x )= 2^x/4
  12. x = log2 (3)
  13. Allison's by $3.95
  14. 3.29
  15. In10/4
  16. The investment is decreasing at the rate of 23% every year.
  17. The function represents exponential growth.
  18. 8,579 years
  19. f (x) = 4(1.05)^n
  20. f(x) = 200(0.92)^x
  21. 1.4 years
  22. f(x) is less than g(x) for the same values of x as x approaches negative infinity.
  23. x = 216
  24. f(x) = (0.005)(1.005)x