of a data set is thedifference betweenthe median of thelower half of a a dataset and the median ofthe upper half of thesame data setInterquartilerangeoutliera value that ismuch greateror much lessthan the othervaluesmedianof a data set is themiddle numberwhen the valuesare placed in orderfrom least togreatestmodethe value thatoccurs themost oftenSometimes atDescribingDataby how thevalues relate toeach other andhow they arespread outDefinitionIQRFree!Find themean 12+ 9 + 12+1043dividedby 5IQR of 13,15, 9, 35,25, 17, 19Q1= 13Q3= 2525-13=121. Put the data inorder from least togreatest.2. Count in fromthe outside to findthe middle value. Steps tofind themedianrangeof a data set is thedifference betweenthe largest valueand the smallestvalue contained inthe data set.meanof a d.s. is thesum of thedata dividedby the numberof data valuesfind therangePut the data set inorder from least togreatest.2. Find the largestvalue and smallestvalue.3. Subtract Solve findthe range11,12,15,15, 13, 12answeris 4Steps tofindingthe meanSteps1. add all numberin the data set.2. divid by thenumber ofaddendsinterquartilerangeIQRof a data set is thedifference betweenthe median of thelower half of a a dataset and the median ofthe upper half of thesame data setInterquartilerangeoutliera value that ismuch greateror much lessthan the othervaluesmedianof a data set is themiddle numberwhen the valuesare placed in orderfrom least togreatestmodethe value thatoccurs themost oftenSometimes atDescribingDataby how thevalues relate toeach other andhow they arespread outDefinitionIQRFree!Find themean 12+ 9 + 12+1043dividedby 5IQR of 13,15, 9, 35,25, 17, 19Q1= 13Q3= 2525-13=121. Put the data inorder from least togreatest.2. Count in fromthe outside to findthe middle value. Steps tofind themedianrangeof a data set is thedifference betweenthe largest valueand the smallestvalue contained inthe data set.meanof a d.s. is thesum of thedata dividedby the numberof data valuesfind therangePut the data set inorder from least togreatest.2. Find the largestvalue and smallestvalue.3. Subtract Solve findthe range11,12,15,15, 13, 12answeris 4Steps tofindingthe meanSteps1. add all numberin the data set.2. divid by thenumber ofaddendsinterquartilerangeIQR

Untitled Bingo - Call List

(Print) Use this randomly generated list as your call list when playing the game. There is no need to say the BINGO column name. Place some kind of mark (like an X, a checkmark, a dot, tally mark, etc) on each cell as you announce it, to keep track. You can also cut out each item, place them in a bag and pull words from the bag.


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  1. Interquartile range
    of a data set is the difference between the median of the lower half of a a data set and the median of the upper half of the same data set
  2. a value that is much greater or much less than the other values
    outlier
  3. of a data set is the middle number when the values are placed in order from least to greatest
    median
  4. the value that occurs the most often Sometimes at
    mode
  5. by how the values relate to each other and how they are spread out
    Describing Data
  6. Definition IQR
  7. Free!
  8. 43 divided by 5
    Find the mean 12 + 9 + 12+ 10
  9. Q1= 13 Q3= 25 25-13= 12
    IQR of 13, 15, 9, 35, 25, 17, 19
  10. Steps to find the median
    1. Put the data in order from least to greatest. 2. Count in from the outside to find the middle value.
  11. of a data set is the difference between the largest value and the smallest value contained in the data set.
    range
  12. of a d.s. is the sum of the data divided by the number of data values
    mean
  13. Put the data set in order from least to greatest. 2. Find the largest value and smallest value. 3. Subtract
    find the range
  14. answer is 4
    Solve find the range 11,12,15, 15, 13, 12
  15. Steps 1. add all number in the data set. 2. divid by the number of addends
    Steps to finding the mean
  16. IQR
    interquartile range