This bingo card has a free space and 24 words: 2 non-colinear members without external forces or support reactions, 3 members, 2 of which are collinear, without external forces or support reactions, ED= 520lb (C) DC= 520lb (C) DB= 0 BC= 450lb (T) AB= 450lb (T) EA= 340lb (C) EB= 0, The force you are solving for and any forces you are given, V = 1.5KN M = 22.5KNm N= 0 KN, Between support reactions, external forces and within distributed loads, P = 2KN X = 0.33m, When we need to find the internal force in a few specific members of a truss, When we need to find the force in every member of a truss, EF= 600 (C) CF= 346 (T) BC= 346 (T) in lb, Fixed Reaction, Roller and Ball and Socket, Ax= 212N Ay= 612N By= 824N, Shear: up Normal: left BM: clockwize, Cut 1: M(x) = -5x V(X) = -5, A positive or negative linear function, The shear equation should be the derivative of the bending moment equation, H I= 900lb (C) JI = 0 DC = 1900 (C) In lb, with equal magnitude and opposite sense, V = 1.25 KN N = 0 M = 18.75 KNm, M = 2J + 3, Ax = -8 Ay = -4 CD = 11.3 in KN, compression, Cut 2: M(x) = -5x+30 V(X) = -5 and M(x) = -(x^3)/3 V(x) = -x^2.
AP Physics 2 | Phonograms | Phonograms | Derckx Bingo | music to my ears!
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