When we needto find theinternal force ina few specificmembers of atrussEF= 600 (C)CF= 346 (T)BC= 346 (T)in lbAx = -8Ay = -4CD = 11.3in KNP = 2KNX =0.33mCut 2:M(x) =-5x+30V(X) = -5A positiveor negativelinearfunction2 non-colinearmemberswithout externalforces orsupportreactionsShear: upNormal: leftBM:clockwizeAx= 212NAy= 612NBy= 824Nwith equalmagnitudeand oppositesenseWhen weneed to findthe force inevery memberof a trussM(x) = -(x^3)/3V(x) = -x^2V = 1.25 KNN = 0M = 18.75KNmFixedReaction,Roller andBall andSocketThe force youare solvingfor and anyforces youare givenCut 1:M(x) = -5xV(X) = -5V = 1.5KNM =22.5KNmN= 0 KNThe shearequation shouldbe the derivativeof the bendingmomentequationH I= 900lb (C)JI = 0DC = 1900(C)In lbcompressionED= 520lb (C)DC= 520lb (C)DB= 0BC= 450lb (T)AB= 450lb (T)EA= 340lb (C)EB= 0M =2J + 3Betweensupportreactions,external forcesand withindistributed loads3 members, 2 ofwhich arecollinear, withoutexternal forcesor supportreactionsWhen we needto find theinternal force ina few specificmembers of atrussEF= 600 (C)CF= 346 (T)BC= 346 (T)in lbAx = -8Ay = -4CD = 11.3in KNP = 2KNX =0.33mCut 2:M(x) =-5x+30V(X) = -5A positiveor negativelinearfunction2 non-colinearmemberswithout externalforces orsupportreactionsShear: upNormal: leftBM:clockwizeAx= 212NAy= 612NBy= 824Nwith equalmagnitudeand oppositesenseWhen weneed to findthe force inevery memberof a trussM(x) = -(x^3)/3V(x) = -x^2V = 1.25 KNN = 0M = 18.75KNmFixedReaction,Roller andBall andSocketThe force youare solvingfor and anyforces youare givenCut 1:M(x) = -5xV(X) = -5V = 1.5KNM =22.5KNmN= 0 KNThe shearequation shouldbe the derivativeof the bendingmomentequationH I= 900lb (C)JI = 0DC = 1900(C)In lbcompressionED= 520lb (C)DC= 520lb (C)DB= 0BC= 450lb (T)AB= 450lb (T)EA= 340lb (C)EB= 0M =2J + 3Betweensupportreactions,external forcesand withindistributed loads3 members, 2 ofwhich arecollinear, withoutexternal forcesor supportreactions

Statics Bingo - Call List

(Print) Use this randomly generated list as your call list when playing the game. There is no need to say the BINGO column name. Place some kind of mark (like an X, a checkmark, a dot, tally mark, etc) on each cell as you announce it, to keep track. You can also cut out each item, place them in a bag and pull words from the bag.


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  1. When we need to find the internal force in a few specific members of a truss
  2. EF= 600 (C) CF= 346 (T) BC= 346 (T) in lb
  3. Ax = -8 Ay = -4 CD = 11.3 in KN
  4. P = 2KN X = 0.33m
  5. Cut 2: M(x) = -5x+30 V(X) = -5
  6. A positive or negative linear function
  7. 2 non-colinear members without external forces or support reactions
  8. Shear: up Normal: left BM: clockwize
  9. Ax= 212N Ay= 612N By= 824N
  10. with equal magnitude and opposite sense
  11. When we need to find the force in every member of a truss
  12. M(x) = -(x^3)/3 V(x) = -x^2
  13. V = 1.25 KN N = 0 M = 18.75 KNm
  14. Fixed Reaction, Roller and Ball and Socket
  15. The force you are solving for and any forces you are given
  16. Cut 1: M(x) = -5x V(X) = -5
  17. V = 1.5KN M = 22.5KNm N= 0 KN
  18. The shear equation should be the derivative of the bending moment equation
  19. H I= 900lb (C) JI = 0 DC = 1900 (C) In lb
  20. compression
  21. ED= 520lb (C) DC= 520lb (C) DB= 0 BC= 450lb (T) AB= 450lb (T) EA= 340lb (C) EB= 0
  22. M = 2J + 3
  23. Between support reactions, external forces and within distributed loads
  24. 3 members, 2 of which are collinear, without external forces or support reactions