V = 1.25 KNN = 0M = 18.75KNmcompressionV = 1.5KNM =22.5KNmN= 0 KNCut 2:M(x) =-5x+30V(X) = -5with equalmagnitudeand oppositesenseA positiveor negativelinearfunctionCut 1:M(x) = -5xV(X) = -53 members, 2 ofwhich arecollinear, withoutexternal forcesor supportreactions2 non-colinearmemberswithout externalforces orsupportreactionsM(x) = -(x^3)/3V(x) = -x^2Ax = -8Ay = -4CD = 11.3in KNThe shearequation shouldbe the derivativeof the bendingmomentequationWhen we needto find theinternal force ina few specificmembers of atrussShear: upNormal: leftBM:clockwizeWhen weneed to findthe force inevery memberof a trussEF= 600 (C)CF= 346 (T)BC= 346 (T)in lbThe force youare solvingfor and anyforces youare givenFixedReaction,Roller andBall andSocketP = 2KNX =0.33mH I= 900lb (C)JI = 0DC = 1900(C)In lbBetweensupportreactions,external forcesand withindistributed loadsED= 520lb (C)DC= 520lb (C)DB= 0BC= 450lb (T)AB= 450lb (T)EA= 340lb (C)EB= 0M =2J + 3Ax= 212NAy= 612NBy= 824NV = 1.25 KNN = 0M = 18.75KNmcompressionV = 1.5KNM =22.5KNmN= 0 KNCut 2:M(x) =-5x+30V(X) = -5with equalmagnitudeand oppositesenseA positiveor negativelinearfunctionCut 1:M(x) = -5xV(X) = -53 members, 2 ofwhich arecollinear, withoutexternal forcesor supportreactions2 non-colinearmemberswithout externalforces orsupportreactionsM(x) = -(x^3)/3V(x) = -x^2Ax = -8Ay = -4CD = 11.3in KNThe shearequation shouldbe the derivativeof the bendingmomentequationWhen we needto find theinternal force ina few specificmembers of atrussShear: upNormal: leftBM:clockwizeWhen weneed to findthe force inevery memberof a trussEF= 600 (C)CF= 346 (T)BC= 346 (T)in lbThe force youare solvingfor and anyforces youare givenFixedReaction,Roller andBall andSocketP = 2KNX =0.33mH I= 900lb (C)JI = 0DC = 1900(C)In lbBetweensupportreactions,external forcesand withindistributed loadsED= 520lb (C)DC= 520lb (C)DB= 0BC= 450lb (T)AB= 450lb (T)EA= 340lb (C)EB= 0M =2J + 3Ax= 212NAy= 612NBy= 824N

Statics Bingo - Call List

(Print) Use this randomly generated list as your call list when playing the game. There is no need to say the BINGO column name. Place some kind of mark (like an X, a checkmark, a dot, tally mark, etc) on each cell as you announce it, to keep track. You can also cut out each item, place them in a bag and pull words from the bag.


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  1. V = 1.25 KN N = 0 M = 18.75 KNm
  2. compression
  3. V = 1.5KN M = 22.5KNm N= 0 KN
  4. Cut 2: M(x) = -5x+30 V(X) = -5
  5. with equal magnitude and opposite sense
  6. A positive or negative linear function
  7. Cut 1: M(x) = -5x V(X) = -5
  8. 3 members, 2 of which are collinear, without external forces or support reactions
  9. 2 non-colinear members without external forces or support reactions
  10. M(x) = -(x^3)/3 V(x) = -x^2
  11. Ax = -8 Ay = -4 CD = 11.3 in KN
  12. The shear equation should be the derivative of the bending moment equation
  13. When we need to find the internal force in a few specific members of a truss
  14. Shear: up Normal: left BM: clockwize
  15. When we need to find the force in every member of a truss
  16. EF= 600 (C) CF= 346 (T) BC= 346 (T) in lb
  17. The force you are solving for and any forces you are given
  18. Fixed Reaction, Roller and Ball and Socket
  19. P = 2KN X = 0.33m
  20. H I= 900lb (C) JI = 0 DC = 1900 (C) In lb
  21. Between support reactions, external forces and within distributed loads
  22. ED= 520lb (C) DC= 520lb (C) DB= 0 BC= 450lb (T) AB= 450lb (T) EA= 340lb (C) EB= 0
  23. M = 2J + 3
  24. Ax= 212N Ay= 612N By= 824N